Display an entry in a view depending on URL

By: Malcolm O\'Reilly | Asked: 09/24/2024
ForumsCategory: Code HelpDisplay an entry in a view depending on URL
Malcolm O\'Reilly asked 3 weeks ago
Hi. I have various blog pages with a different bird name in each URL. I would like to display the same view on each page, but the view set up to display a matching form entry for that specific blog (eg: the 'eagle' form entry is displayed only when 'eagle' appears in the blog post URL). Is this even possible? Or would I be better creating a different view for each bird species, or using shortcodes? TIA
4 Answers
Victor Font answered 3 weeks ago
You can do this with a single view filtered on bird species. You pass the parameter in the URL: my-view.com?species=eagle. In your view filter you set species to equal [get param='species']
Malcolm O\'Reilly answered 3 weeks ago
Thanks! I'm not very familiar with get param. When you refer to the URL 'my-view.com?species=eagle'?, do you mean the URL of the blog post?  Eg: https://arcguiding.com/blog/nature/scottish-crossbill/ I get roughly how the filtering is set up, but not the previous part:  how to pass the parameter. This doesn't mean changing the corresponding blog post URL does it?  Thanks for your patience. 
Victor Font replied 3 weeks ago

You asked about how to filter a view. I already told you, views have nothing to do with blog posts.

Rob LeVineRob LeVine answered 3 weeks ago
I think you some miscommunication here, so I'll give it a shot. What I think you're asking for is a way to parse the URL (not the parameters) and use the result to filter a view. There are two ways I can think of to do that, the first will definitely work though it's big-time custom and the second I assume will work. The first is to make the content of your view a shortcode and the shortcode parses the URL, figures out which bird type, and then returns the HTML needed to generate the output. The second is to use frm_where_filter. You set up your view however you want and use that hook to set the bird parameter based on the URL.
Malcolm O\'Reilly answered 3 weeks ago
Hey thanks Rob for your help. It's all fixed now, super simple. I'm no expert - I was trying with the Gutenberg Formidable Views block and hadn't understood that the value could be passed via the shortcode instead. All fixed now, thanks 😁 (also ran into a big ol bug cos using an old version of the plugin) 

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