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How do I set the first day of the week in an inline date field?

By: Paul Yates | Asked: 11/21/2022
Forums › Category: Code Help › How do I set the first day of the week in an inline date field?
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Paul Yates asked 2 years ago

I've tried this code but not sure why it's not working:
 

add_filter('frm_date_field_js', 'change_start_day');
function change_start_day($args){
if($args['field_id'] == 10){
$args['firstDay'] = 1;
}
return $args;
}

3 Answers
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Rob LeVineRob LeVine Staff answered 2 years ago

I'm not sure where you got that code, but it ain't ever gonna work :). Substitute the field KEY of the date field in where you see 'rqaj9'.
 

add_filter('frm_date_field_js', 'change_start_day');
function change_start_day($field_key) { /* the examples use "field_id" but it's the key */
	if ($field_key == 'field_rqaj9') {
		echo ',firstDay: 1';
	}
}
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Paul Yates answered 2 years ago

xD thanks.
That works but doesn't seem to work at all with the advanced datepicker options. I'm guessing it's just overwriting all the options?

Rob LeVineRob LeVine Staff replied 2 years ago

It appends a "parameter" javascript that is the datepicker. It should be used for all parameters that aren't covered by the Formidalbe datepicker addon as long as you have the correct syntax.

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Paul Yates answered 2 years ago

Yeah I suspect a syntax error caused by it being an inline date field.
I used this instead and it works:

add_filter( 'frm_date_field_options', 'add_blackout_dates', 30, 2 );
function add_blackout_dates( $js_options, $extra ) {
	if ( $extra['field_id'] === 'field_2u7es' ) {
		$js_options['options']['firstDay'] = 1;
	}
	return $js_options;
}

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